Question

The value of [ 3 ]^-1 ÷ [3]^-2 is​

Answer 1

Answer:

Step-by-step explanation:

I think I can't because I don't know about it

Answer 2

Answer:

3

Step-by-step explanation:

${3}^{ - 1} \div {3}^{ - 2} \\ = {3}^{ - 1 - ( - 2)} \\ = 3^{ - 1 + 2} \\ = {3}^{2 - 1} \\ = {3}^{1} \\ = 3$

Hence

${3}^{ - 1} \div {3}^{ - 2} = 3$

Remember when bases (↓here x) are same,

${x}^{m} \times {x}^{n} = {x}^{m + n} \\ {x}^{m} \div {x}^{n} = {x}^{m - n} \\ ( {x}^{m} )^{n} = {x}^{m \times n}$

By using the second one we solved this question.

hope it helps.