Math, asked by deepajoy944, 2 months ago

the value of (3^-1+ 4^-1+5^-1)^0 is _____​

Answers

Answered by Moncheri06
10

\huge \mathbb\fcolorbox{black}{lavenderblush}{Answer}

Step-by-step explanation:

( {3}^{ - 1}  +  {4}^{ - 1}  +  {5}^{ - 1} )^{0}  \\ ( \frac{1}{3}  +  \frac{1}{4}  +  \frac{1}{5} )^{1}  \\  (\frac{1 \times 20 + 1 \times 15 + 1  \times12 }{60} ) ^{1} \\ ( \frac{20 + 15 + 12}{60}) ^{1}   \\  (\frac{47}{60} ) ^{1}  \\  \frac{47}{60}

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Answered by prithapaul35
1

No need to solve inside as something^0 = 1so answer is 1

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