Math, asked by jijur31121999, 1 month ago

The value of [3]+11([5]+11[6])[3]+11([5]+11[6]) is​

Answers

Answered by nagabushannagabushan
1

Answer:

3+11([5]+11[6])[3]+11([5]+11[6]

=3+11(5+66)[3]+55+66

=3+11(71)(3)+121

=3+2343+121

=2346+121

=2467

Step-by-step explanation:

hope this helped you

Mark me as brainlist☺️

Answered by payalchatterje
0

Answer:

The value of [3]+11([5]+11[6])[3]+11([5]+11[6]) is 3127.

Step-by-step explanation:

Given,[3]+11([5]+11[6])[3]+11([5]+11[6])

By BODMAS rule,we can solve this problem.

We know,

BODMAS rule always follow the following sequence,

Bracket - Of - Division - Multiplication - Addition - Subtraction.

Here,

[3]+11([5]+11[6])[3]+11([5]+11[6])

First we are removing third bracket,

3 + 11 \times (5 + 11 \times 6) \times 3 + 11\times(5 + 11 \times 6)

 = 3 + 11 \times 3(5 + 66) + 11(5 + 66) \\  = 3 + 33 \times 71 + 11 \times 71 \\  = 3 + 2343 + 781 \\  = 3127

Required answer is 3127.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

Similar questions