Question

The value of [(3^2)^2]^-1 is _____


A. 81 B. -81 C. -0.0123 D. 0.0123

Answer 1

SOLUTION:-

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Answer 2

Step-by-step explanation:

$= > ( {3}^{2} ) {}^{2} - 1 \\ \\ = > ({9}^{2} ) ^{-1}\\ \\ = > 81^{-1} \\ \\ = > 1/81= 0.0123$

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