Question

The value of (3+2√2) (3-2√2) is 

    1
    9-2√2
    9+2√2
    0​

Answer 1

Answer:

(a). cosx (3 sin x + cos x + 3) dy = (1 +

Answer 2

=>(3+2√2) (3-2√2)

=>(3)^2-(2√2)^2

=>9-8

=>1

Therefore,Option A is correct,i.e.,1