Question

the value of (3√2+2√3)×(3√2-2√3)​

Answer 1

Answer:

198

Step-by-step explanation:

[3+2(2)^1/2]^-3+[3-2(2)^1/2]^-3

=1/[3+2(2)^1/2]^3+1/[3-2(2)^1/2]^3

=[{3-2(2)^1/2}^3+{3+2(2)^1/2}^3]÷[{3+2(2)^1/2}^3×{3-2(2)^1/2}^3

=[{3-2(2)^1/2+3+2(2)^1/2}^3-3×{3-2(2)^1/2}{3+2(2)^1/2}{3-2(2)^1/2+3+2(2)^1/2}]÷[3^2–{2(2)^1/2}^2]

=[6^3-3(9-8)(6)]÷[9-8]

=216-18

=198