CBSE BOARD XII, asked by Anonymous, 3 days ago

The value of (3√3.5+3√2.5)((3√3.5)2−3√8.75+(3√2.5)2) is :​

Answers

Answered by vg8161786
0

Explanation:

Description for Correct answer:

(3.5−−−√3+2.5−−−√3){(3.5−−−√3)2−8.75−−−−√3+(2.5−−−√3)2}

x=3.5−−−√3y=2.5−−−√3

=(x+y)(x2−xy+y2)

=x3+y3

=(3.5−−−√3)3+(2.5−−−√3)3

=3.5+2.5=6

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