the value of√3-√5×√5+√3/2
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Answer:
Solution
[3–
5
]/[3+2
5
]=−19/11+a
5
Let us consider LHS
[3–√5]/[3+2
5
]
Rationalize the denominator,
[3–
5
]/[3+2
5
]=[(3–
5
)(3–2
5
)]/[(3+2
5
)(3–2
5
)]
=[3(3–2
5
)–
5
(3–2
5
)]/[32–(2
5
)2]
=[9–6
5
–3
5
+2.5]/[9–4.5]
=[9–6
5
–3
5
+10]/[9–20]
=[19–9
5
]/−11
=−19/11+9
5
/11
So when comparing with RHS
−19/11+9
5
/11=−19/11+a
5
Hence, the value of a=9/11
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