Math, asked by yav76, 1 day ago

the value of ∆^3 (ax^3+bx^2+cx+d) is​

Answers

Answered by naveenkannan1sbscvv
0

Answer:

f(x)=ax

3

+bx

2

+cx+d

⇒f

(x)=3ax

2

+2bx+c

For no extrema, f should have zero turning points, i.e. above quadratic have no real roots.

⇒(2b)

2

−4⋅3a⋅c<0

⇒b

2

<3ac

Answered by Anonymous
0

Answer:

∆^3ax^3+∆^3bx^2+∆^3cx+d∆^3

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