Question

the value of( 3 root -root2 ) (3root+root 2)=

Answer 1

$\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>$

$( \sqrt{3} - \sqrt{2} )( \sqrt{3} + \sqrt{2} )$

$= {( \sqrt{3} \: ) }^{2} - {( \sqrt{2} )}^{2}$

$= 3 - 2$

$= 1$

$</p><p></p><p>\displaystyle\textcolor{red}{Please \: Mark \: it \: Brainliest}$

Answer 2

Answer:(√3-√2)(√3+√2)

Formula (A-B)(a+b)=a²-b²

Here a=√3 and b=√2

So answer is (√3)²-(√2)²=3-2=1

Step-by-step explanation: