Question

the value of √32+√48÷√8+√12
is equal to __________​

Answer 1

Answer:

$4 \sqrt{10} - 8 \sqrt{6} + 2 \sqrt{5r} - 4 \sqrt{3r} \frac{7}$

Answer 2

Answer:

2

Step-by-step explanation:

√32+√48 ÷√8+√12

=√4^2×2+√4^2×3÷√2^2×2+√2^2×3

=4√2+4√3÷2√2+2√3(Here in 4^2 square and roots have cancelled and in 2^2 square and roots have cancelled)

=4(√2+√3)÷2(√2+√3) (Here in numerator 4 and in denominator 2 has taken commom)

=In the above step we should divide numerator and denominator

=That employs : 2 divides 4 which is equal to 2 and √2+√3 are their in numerator and denominator. So they will be cancelled.

=So finally the answer is 2