Question

The value of √32+√48/√8+√12 is equal to​

Answer 1

Answer:

$\sqrt{32} + \sqrt{48} \div \sqrt{8} + \sqrt{12} \\ \\ \\ = \frac{ \sqrt{32} \times \sqrt{48} }{ \sqrt{8} \times \sqrt{12} } = \frac{ \sqrt{8 \times 4} \times \sqrt{12 \times 4} }{ \sqrt{8} \times \sqrt{12} } \\ \\ = \frac{2 \sqrt{8} \times 2 \sqrt{12} }{ \sqrt{8} \times \sqrt{12} } = \frac{2( \sqrt{8} \times \sqrt{12} )}{ \sqrt{8} \times \sqrt{12} } = \\ \\ = 2$

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Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

$\textsf{Given}$

$\sf{ \frac{ \sqrt{32} + \sqrt{48} }{ \sqrt{8} + \sqrt{12} } }$

$\sf{ = \frac{ \sqrt{16 \times 2} + \sqrt{16 \times 3} }{ \sqrt{4 \times 2} + \sqrt{4 \times 3} } }$

$\sf{ = \frac{4 \sqrt{2} + 4 \sqrt{3} }{2 \sqrt{2} + 2 \sqrt{3} } }$

$\sf{ = \frac{4 ( \sqrt{2 } + \sqrt{3}) }{2( \sqrt{2} + \sqrt{3} )} }$

$\sf{ = \frac{4}{2} }$

$\sf{ = 2 \:Ans. }$