the value of 3ab + 2b2 – 3a + 6 equals to -18, when b = 0? find the value of a
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given equation
3ab + 2b^2 - 3a + 6 = -18
given value of b = 0
putting b = 0 in the equation
we get, 3a(0) + 2(0)^2 - 3a +6 = -18
0 + 2(0) - 3a +6 = -18
0 -3a +6 = -18
6-3a = -18
3(2-a) = 3(-6)
2-a = -6
-a = -6 -2
-a = -8
-1(a) = -1(8)
a = 8
Step-by-step explanation:
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