Question

the value of 3sin 70° sec20° +2sin 49 ° sec51 ° is​

Answer 1

YOUR ANSWER:

-->3× sin(90-20)×sec20 +2×sin(90-51)×sec51

-->3×cos20×sec20 + 2×cos51×sec51

● [ cos20 & sec20 gets cancelled ]

● [ cos51 & sec51 gets cancelled ]

finally,

-->3(1) + 2(1)

-->5

ANSWER: 5

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