Question

the value of (3x^3+9x^2+27x)÷3x is

Answer 1

it's answer is (d) bro

Answer 2

Heya ! Here is u r Ans ➡➡➡
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✔Ans ➡ Option D

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SOLUTION➡

$= \frac{(3x {}^{3} + 9x {}^{2} + 27x) }{3x}$

$= \frac{3x(x {}^{2}3x + 9) }{3x}$

$= reduced \: the \: fraction \: 3x$

$= x {}^{2} + 3x + 9$

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