Math, asked by vijidevi, 1 day ago

The value
of
[3x3 + 9x0² +27 )÷3x is

Answers

Answered by dhavalarora0902

1

Answer:

using BODMAS rule

=[9 + 0 +27 ]/ 3x

=[36] / 3x

=12/x

Answered by kiseemboskylar

0

(3×3+9×0×0+27)÷3x

9+0+27)÷3x

36÷3x

=12x

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