Question

the value of (4^0 - 3^1) X 6^2 is _________

Answer 1

$\bf \red{Answer:-}$

$\tt{ {(4}^{0} - {3}^{1} ) \times {6}^{2} }$

$= \tt{(1 - 3) \times 36}$

$= \tt{ - 2 \times 36}$

$= \tt{{ \underline{ \underline{ \purple{- 72}}}}}$

Answer 2

answer = -72 plz mark me as brainliest