Math, asked by prachisingh338, 1 month ago

The value of ⁴√³√x² please find the answer​

Answers

Answered by ItzCadburyAnshi
4

Answer :-

\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}4</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×4</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x12</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x122</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x122=x</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x122=x6</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x122=x61</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x122=x61=</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x122=x61=6</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x122=x61=6x</u></em></p><p></p><p><em><u>[tex]\begin{gathered} \sqrt[4]{ \sqrt[3]{ {x}^{2} } } \\ = {x}^{ \frac{2}{3 \times 4} } = {x}^{ \frac{2}{12} } = {x}^{ \frac{1}{6} } = \sqrt[6]{x} \end{gathered}43x2=x3×42=x122=x61=6x

Answered by glassoptions917
2

Step-by-step explanation:

888,87779,545=457(4445)

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