Question

The value of 4.4 g co2 at NTP will be

Answer 1

Answer ⇒ 2.24 L.

Explanation ⇒

We know that, 1 mole of any gas at S.T.P. occupies the volume of 22.4 L.

Now, To find the volume of 4.4 gm of Carbon dioxide, we should find the no. of moles of Carbon dioxide.

∴ No. of moles of Carbon dioxide = Mass of Carbon dioxide/Molar mass of Carbon dioxide.

∵ Molar mass of Carbon dioxide = 44 gm.

∴ Moles = 4.4/44

∴ Moles = 0.1 moles.

Now,

∵ 1 mole occupies 22.4 Vol.

∴ 0.1 moles occupies the vol. of 22.4 × 0.1 = 2.24 L.

Hence, the volume occupied by the 4.4 gm of Carbon dioxide is 2.24 L.

Hope it helps.

Answer 2

IN THE GIVEN QUESTION WE HAVE TO CALCULATE THE VOL. OF CO2 AT NIN GIVEN AMT  OF CO2

We know at Normal Temperature Presssure

temperature=273k

there moles of C(O)2=WEIGHT OF CO2/MOLECULAR MASS

=4.4/44=0.1 MOLE

Therefore moles of CO2 =0.1

Now we know that at NTP

1 mole of CO2 Occupies 22.4 L

THEREFORE 0.1 MOLE OF CO2 WILL OCCUPY =0.1*22.4=2.24 Litres of CO2