The value of ∑40r=1 1/(r+1)(r+2)=
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Since, in the question it is given as the sphere's movement is in the direction of positive x and also it is having a angular momentum of ω, the velocity of the center of the the sphere is given as ωR/3 where the sphere is rotating in the anticlockwise direction.
So, the velocity at the bottom of the sphere will be in relative to the velocity of the center part of the sphere. So, the velocity will be ω + ωR/3 which on solving we will get that 4ωR/3.
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