Math, asked by humanbeing73, 5 hours ago

The value of
(4a²-9b²)³+(9b²-16c²)³+(16c²-4a²)³/(2a-3b)²+(3b-4c)³+(4c-2a)³ is
1. 3abc
2.3(2a+3b)(3b+4c)(4c+2a)
3.(2a +3b)(3b-4c)(4c+2a)
4. 1​

Answers

Answered by itsmesike
1

Answer:

the value of ((4a^2-9b^2) ^3 +(9b^2-16c^2)^3 + (16c^2 - 4a^2)^3)/((2a- 3b)^3 + (3b-4c)^3 +(4c - 2a )^3)

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