the value of 4x²-3x+3 at x=1 is _______
Answers
4x^2–3x-1
(4x+1)(x-1)
That’s as far as I can take you unless you set this expression equal to zero 0. Then it becomes a quadratic equation with two solutions, and we can solve for both.
(4x+1)(x-1) = 0
Set each set of parentheses equal to zero, and then solve for x:
4x+1 = 0
4x = -1
x = -1/4
x-1 = 0
x = 1
So there are two possible solutions to this equation. Next we’ll prove they are both valid by substituting for x in the original equation.
4x^2–3x-1 = 0
x = 1
4*1^2–3*1–1 = 0
4*1–3–1 = 0
4–3–1 = 0
1–1 = 0
0 = 0
So x = 1 is a valid solution to this equation. Now for the other value:
4x^2–3x-1 = 0
x = -1/4
4*(-1/4)^2 - 3*-1/4 - 1 = 0
4(1/16) - (-3/4) - 1 = 0
4/16 + 3/4 - 1 = 0
Convert to like terms; the LCD is 16:
4/16 + 12/16 - 16/16 = 0
16/16 - 16/16 = 0
0 = 0
So x = 1 OR x = -1/4 are both valid solutions to this equation because each results in this equation being a true statement.
hope this helps you (≡^∇^≡)
Answer:
Here is your answer
Step-by-step explanation:
here given x = 1
4(1)² - 3(1) + 3
4 - 3 + 3
= 4
So, the value of 4x²-3x+3 at x=1 is 4
Hope it helps....