Question

The value of –4x2 y2 + 6xy + 8x + 12y – 1, when x= –2, y = –1 is pls say with steps plsss​

Answer 1

-4x²y²+6xy+8x+12y-1

Putting x=-2 & y=-1

-4(-2)²(-1)²+6×(-2)×(-1)+8×(-2)+12×(-1)-1

-16+12-16-12-1

-33

Answer 2

Refer the pic.

Hope it helps.