Math, asked by DEVIPRASAD321, 1 year ago

the value of( 52 + 6√43) whole power 3 by 2 - (52 - 6 root 43) whole power 3 by 2 please answer


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Answers

Answered by sprao534
18
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Answered by visalavlm
3

Answer:

The value of  (52+ (2)\sqrt{43(9)} )^{\frac{3}{2} } - (52-(2)\sqrt{43(9)} )^{\frac{3}{2} } is  828.

Step-by-step explanation:

Given that (52 + 6\sqrt{43} )^{\frac{3}{2} } - (52-6\sqrt{43})^{\frac{3}{2} }

((52+ (2)(3)\sqrt{43} )^{\frac{3}{2} } - (52-(2)(3)\sqrt{43} )^{\frac{3}{2} }

(52+ (2)\sqrt{43(9)} )^{\frac{3}{2} } - (52-(2)\sqrt{43(9)} )^{\frac{3}{2} }

We know that (a+b)³ = a³ +b³+3a²b+3ab²

(a-b)³ = a³ -b³ -3a²b+3ab²

(a+b)² = a²+2ab+b²

(aⁿ)ˣ = aⁿˣ

\sqrt{(52+6\sqrt{43})^{3}  } = \sqrt{((43+9)+2(3)\sqrt{43})^{3}  }

                       = \sqrt{((\sqrt{43})^{2}+(3)^{2}+2(\sqrt{43})(3))^{3}     }

                      =\sqrt{(((\sqrt{43)}+3)^{2})^{3}   }

                     =[(\sqrt{43} +3)^{2} ]^{\frac{3}{2} }

                     =(√43+3)³           ---------------------------(1)

\sqrt{(52-6\sqrt{43})^{3}  } = \sqrt{((43+9)-2(3)\sqrt{43})^{3}  }

                       = \sqrt{((\sqrt{43})^{2}+(3)^{2}-2(\sqrt{43})(3))^{3}     }

                      =\sqrt{(((\sqrt{43)}-3)^{2})^{3}   }

                     =[(\sqrt{43} -3)^{2} ]^{\frac{3}{2} }

                     =(√43-3)³     ---------------------------(2)

From the question equation(2) subtracting from equation(1)

That is

(52+ (2)\sqrt{43(9)} )^{\frac{3}{2} } - (52-(2)\sqrt{43(9)} )^{\frac{3}{2} }=   (√43+3)³ - (√43-3)³

=[(√43)³+(3)³+3(√43)²(3)+3(√43)(3)²] - [(√43)³ -(3)³-3(√43)²(3)+3(√43)(3)²]

=(√43)³+(3)³+3(√43)²(3)+3(√43)(3)² - (√43)³ +(3)³+3(√43)²(3)-3(√43)(3)²]

=3×43×3+27+3×43×7+27

=387×2+54

=774+54

= 828.

Therefore, (52+ (2)\sqrt{43(9)} )^{\frac{3}{2} } - (52-(2)\sqrt{43(9)} )^{\frac{3}{2} }= 828.

                   

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