the value of 5cos theta +3cos (theta+π/3)+3
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Solution :
3cos(θ+π3)=3{cosθcosπ3−sinθsinπ3}
=3cosθ⋅12−3sinθ3–√2
=32cosθ−33–√2sinθ
5cosθ+3cos(θ+π3)+3
=5cosθ+32cosθ=33–√2sinθ+3
=12(13cosθ−33–√sinθ)+3
=169+27−−−−−−−√2⋅cos(θ+ϕ)+3
=196−−−√2cos(θ+ϕ)+3
=7cos(θ+ϕ)+3
−4≤7cos(θ+ϕ)+3≤10
option c is correct.
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