The value of (5x-2)3 + (3-4x)3 + 3(x+1) (5x-2) (3-4x) is
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We have, 4a2 = 2 × 2 × a × a, 4ab = 2 × 2 × a × b and, 4ca = 2 × 2 × c × a The three terms have 2, 2 and a as common facotrs - 4a2 + 4ab - 4ca ...
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