Math, asked by ashmit78, 1 year ago

The value of (6^-1 – 8^-1)^-1 is what ?

Answers

Answered by Anonymous
1

=(6^-1-8^-1)^-1

=(1/6-1/8)^-1

=(8-6/48)^-1

=(2/48)^-1

=48/2

= 24

plzz mark me brainliest..

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