The value of 64⁻¹/³ (64¹/³ -64²/³ ) , is
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h(x+2)-3. (x+3)²-3 or x²+6x+3 ... f( x)= -2x+7. Find f⁻¹(x). f⁻¹(x)= (x-7)/-2 ... 64⁻¹/³. 1/64¹/³=> What's the third root of 64?=> 4.
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