Question

The value of 6a²b²-4ab , when a=2 and b=(-1) is ____________ .

Answer 1

Given :

a = 2

b = (-1)

To Find :

The value of 6a²b²-4ab

Solution :

∴ 6a²b² - 4ab

Placing the value of a = 2 and b= -1 in 6a²b² - 4ab

= 6×(2)²(-1)² - 4×2×(-1)      [ ∵ -1×(-8) = +8]

= 6×4×1 + 8

= 24 + 8

= 32

∴ The value of 6a²b²- 4ab is 32.

Answer 2

• The value of 6a²b²- 4ab , when a = 2 and b = (-1) is 32 .

Given :-

• a = 2
• b = (-1)

To Find :-

• 6a²b²- 4ab

Formula used :-

• (-1)^2n = 1
• (-)(-n) = n { If a bracket is preceded by a minus sign , negative sign inside bracket changes into positive sign. }

Solution :-

given expression is,

→ 6a²b²- 4ab

putting a = 2 and b = (-1) we get,

→ 6 × (2)² × (-1)² - 4 × 2 × (-1)

using 2² = 4 and (-1)² = 1 now,

→ 6 × 4 × 1 - 8 × (-1)

→ 24 - (-8)

using above told rule of sign change ,

→ 24 + 8

→ 32 (Ans.)

Hence, the required value is equal to 32 .

Learn more :-

solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method

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