Math, asked by bhavikas1208, 1 month ago

the value of (7^-1 - 8^-1)^-1 -(3^-1 - 4^-1)^-1​

Answers

Answered by Amitbisht2007
1

Answer:

0 is the answer

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Answered by kk3871334
2

Answer:

 {( {7}^{ - 1} -  {8}^{ - 1})  }^{ - 1}  -  {( {3}^{ - 1}  -  {4}^{ - 1}) }^{ - 1}  \\  =  { (\frac{ 1}{7}  - \frac{1}{8} )}^{ - 1}  -  {( \frac{1}{3}  -  \frac{1}{4}) }^{ - 1}  \\  =  {( \frac{8 - 7}{56} )}^{ - 1}  -  {( \frac{4 - 3}{12}) }^{ - 1}  \\  =  {( \frac{1}{56} )}^{ - 1}  -  {( \frac{1}{12}) }^{ - 1}  \\  = 56 - 12 \\  = 44

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