Question

The value of (√7)6 is equal to

Answer 1

294 first we should remove the root bracket

Then it will 49 then 49×6

Answer 2

Answer:

The value of (√7)6 is equal to 15.8745079.

Step-by-step explanation:

Given term is $(\sqrt{7})6$

We know value of $\sqrt{7} = 2.64575131$

So, required value of (√7)6

$= 2.64575131 \times 6 \\ = 15.8745079$

Some extra root value of others digits,

$\sqrt{1} = 1 \\ \sqrt{2} = 1.414213 \\ \sqrt{3} = 1.7321 \\ \sqrt{4} = 2 \\ \sqrt{5} = 2.23606793 \\ \sqrt{6} = 2.44948974 \\ \sqrt{8} = 2.82842712 \\ \sqrt{9} = 3 \\ \sqrt{10} = 3.16227766$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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