Question

The value of √7^log5 - √5^log7 is equal to? ​

Answer 1

Answer:

√7^log5 - √5^log7 = 0.

❤️Hope it will help you.❤️

Answer 2

SOLUTION

$= > \sqrt{7} {}^{(log5)} - \sqrt{5} {}^{(log7)} \\ = > (7 {}^{ (\frac{1}{2} ) {}^{(log5)} } - (5 {}^{( \frac{1}{2}) } {}^{(log7)} \\ = > (7) {}^{( (\frac{1}{2})log5) } - (5) {}^{(( \frac{1}{2})log7) } \\ = > (7) {}^{(log \sqrt{5}) } - (5) {}^{(log \sqrt{7}) } \\ = >( 10 {}^{(log7) {}^{(log5)} }) - (10 {}^{(log5) {}^{(log7)} } ) \\ = > 10 {}^{(log7 \times log5)} - 10 {}^{(log5 \times log7)} \\ = > 10 {}^{(log5 \times log7)} - 10 {}^{(log5 \times log7)} \\ \\ = > 0$

hope it helps ☺️