Question

The value of 7^n+3+14×7^n+4/7^n+4 is equal to

Answer 1

$\red{ The \: value \: of \: \frac{7^{n+3}+ 14\times 7^{n+4}}{7^{n+4}}}$

$= \frac{7^{n+3}+ 14\times 7^{(n+3)+1}}{7^{(n+3)+1}}$

$= \frac{7^{n+3}+ 14\times 7^{(n+3)} \times 7}{7^{(n+3)}\times 7}$

$= \frac{ \cancel {(7^{n+3}) }( 1 + 14 \times 7) }{\cancel {(7^{n+3})}\times 7 }$

$=\frac{ 1 + 14 \times 7}{7}$

$= \frac{1 + 98}{7}$

$= \frac{99}{7}$

Therefore.,

$\red{ The \: value \: of \: \frac{7^{n+3}+ 14\times 7^{n+4}}{7^{n+4}}} \green { = \frac{99}{7}}$

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Answer 2

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