Question

the value of 7 sec2A minus 7 tan2A is equal to​

Answer 1

Answer:

7

Step-by-step explanation:

7sec^A -7tan^2A

=7[sec^A-tan^A]

=7(1)

=7

hope it helps you::))

Answer 2

7sec^2A -7tan^2A

=7[sec^2A - tan^2A]    ( $tan^{2}$ + 1 = $sec^{2}$

                                       ⇒ $tan^{2}$ - $sec^{2}$ = (-1) )

=7(-1)

= -7