Question

the value of [(-73)÷12]÷3​

Answer 1

Answer:

Using BODMAS

(72 - 12 \div 3 \times 2) + (18 - 6) / 4(72−12÷3×2)+(18−6)/4

( 72 - 12/6 ) + 12 \div 4(72−12/6)+12÷4

(72 - 2) + 3(72−2)+3

70+ 370+3

7373