Math, asked by sumanbidhan1, 2 months ago


The value of {(81)^1/4}^-1 is

(i) 3
(ii) - 3
(iii)1/3
(iv)-1/3​

Answers

Answered by lokeshk7878
0

Answer:

First We will do factor of 81.

We will get 81= 3*3*3*3

3 Ki power 4

3)^4*1/4 -1

4 to 1/4 cancel because of multiple

We will get

3-1 = 2

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