Math, asked by rajbhuina, 1 day ago

The value of (8ax-3b)(8ax+b) is
64 a^2 x^2 + 16axb - 3 b^2

64 a^2 x^2 - 16axb + 3 b^2

64 a^2 x^2 - 16axb - 3 b^2

Answers

Answered by chandan454380
0

Answer:

The answer is 64a^2x^2-16ax-3b^2

Step-by-step explanation:

  (8ax-3b)(8ax+b)

=8ax(8ax+b)-3b(8ax+b)\\=64a^2x^2+8abx-24abx-3b^2\\=64a^2x^2-16ax-3b^2

Answered by Jiya0071
11

Answer:

64 a^2 x^2 - 16axb - 3 b^2

hope it helps

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