Question

the value of 8x-1/8x³ is:​

Answer 1

Answer:

Bhai answer sahi hai Kya aagr question me pure ka bhag ho to bata dena

Answer 2

Answer:

$8x - \frac{1}{8 {x}^{3} } = 0 \\ 8x = \frac{1}{8 {x}^{3} } \\ 8x \times 8 {x}^{3} = 1 \\ 64 {x}^{4} = 1 \\ {x}^{4} = \frac{1}{64} \\\blue{\mathfrak{\underline{\large{Square \: root \: on \: both \: side}}}:} \\ {x}^{2} = \frac{1}{8} \\ x = \frac{1}{2 \sqrt{2} } \\ 8x - \frac{1}{8 {x}^{3} } = 0 \\ 8 \times \frac{1}{2 \sqrt{2} } - \frac{1}{8 \times { (\frac{1}{2 \sqrt{2} }) }^{3} } \\ \frac{4}{ \sqrt{2} } - 2 \sqrt{2} \\ = 0.verified \\ \\\red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$