Question

the value of 9 second square A - 9 tan square A is
pls fast step by step
pls fast​

Answer 1

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the value of 9 second square A - 9 tan square A is

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$\sf{ Sec^2 theta \:and \:cosec^2 theta}$ are tan and cot forms then apply Am greater are equal to GM.

Composite of the square function are secant function based on the Item, Value with the second derivative having impact on

$\sf \: 2\sec^4x + 4\sec^2x \tan.$

When comparing to all the aspects are derived accordingly

$\sf \: =9 sec^2x - 9tan^2x \\ { \sf</p><p>= 9 (sec^2x -tan^2x)} \\ { \sf</p><p> = 9×1 }\\ { \sf</p><p>= 9}$

Answer 2

Answer:

$: \implies\sf 9 \:sec^2 \:A - 9 \:tan^2 A$

$: \implies\sf 9 \:(1 + tan^{2} )\:A - 9 \:tan^2 A \: \: \: \: \bigg \lgroup \bf As \: sec^2 \: A = 1 + tan^2 \: A \bigg \rgroup$

$: \implies\sf 9 + \cancel {9\:tan^2 \:A }- \cancel{9 \:tan^2 A }$

$: \implies\sf 9 + 0$

$: \implies\huge \underline{\boxed{\sf 9 } }$