Physics, asked by farahalrafeeq, 10 months ago

The value of (98)^1/2 according to binomial theorem is?

Answers

Answered by niyati2dinesh
1

Answer:

7√2 is the answer...........

Answered by VivanTopper
2

Answer:

9.9

Explanation:

=(98)^1/2

(100-2)^1/2

(100(1-2/100))^1/2

(1+x)^n= 1+nx if x is less than 0

in equation 1-2/100 x is less than zero

so

√100(1-2/100×1/2)

10(1-1/100)

10(99/100)

= 99/10

=

9.9

in three decimal places =9.899

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