The value of (98)^1/2 according to binomial theorem is?
Answers
Answered by
1
Answer:
7√2 is the answer...........
Answered by
2
Answer:
9.9
Explanation:
=(98)^1/2
(100-2)^1/2
(100(1-2/100))^1/2
(1+x)^n= 1+nx if x is less than 0
in equation 1-2/100 x is less than zero
so
√100(1-2/100×1/2)
10(1-1/100)
10(99/100)
= 99/10
=
9.9
in three decimal places =9.899
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