Question

The value of a^3+a^2b+ab^2+b^3, by applying a =1, b=-2


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Answer 1

Answer:

a³+ 3a²b + 3ab² + b³

= (a+b)³

Now putting a=1 , b=-2 we get,

(a+b)³= (1-2)³

=(-1)³

=-1

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Answer 2

Answer:

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