The value of a^3+ b^3 if 3^a=81 and 7^b=343 is:
Answers
Answered by
0
Answer:
91
Step-by-step explanation:
3^a = 81
3^a = 3⁴
taking 3 out , as it is the same base
so,
a = 4
7^b = 343
7^b = 7^3
so,
b = 3
ACQ,
a³ + b³ = 4³ + 3³
= 64 + 27
= 91
Answered by
0
Answer:
Third proportional is 343
So, ⟹A:B::B:343
Doing product of the extremes and product of mean, we get
B
2
=343A⟶(1)
Also, A:B=1:7
So, B=7A
So, (7A)
2
=343A
A=7
B=7A=49
A+B=49+7=56
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