Question

The value of a acceleration due to gravity at a point p inside the earth and at another point q

Answer 1

0           ples conform  it ....

Answer 2

$g_{1}=\dfrac{g}{2}$

Explanation:

The complete question:

The value of acceleration due to gravity at a point P inside the earth and at another point Q outside the earth is $\dfrac{g}{2}$. Maximum possible distance in terms of radius of earth R between P and Q is:

The value of acceleration due to gravity at height(h) is:

$g_{1 }= g.(\dfrac{R}{R+h})^2$

Where, h is the height of the particle Q, outside the earth

The value of acceleration due to gravity inside the earth is:

$g_{1}= g(1-\dfrac{d}{R} )$

Where, d is the depth of the particle P, inside the earth)

Put $g_{1}=\dfrac{g}{2}$ , we get

Both the cases , we get the value of h and d

Adding both h and d, we will get the maximum possible distance in terms of radius of earth.