The value of (a+b)2-(a-b)2
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Answer:
(a+b)²-(a-b)²
=a²+b²+2ab-a²-b²+2ab
=4ab
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sᴏʟᴜᴛɪᴏɴ⤵️
Given:-evaluate (a+b)²-(a-b)²
To solve the sum we used the formula of 4ab
Formula of 4ab=(a+b)²-(a-b)²
so the your answer =4ab
but now we prove this
so,LHS=(a+b)²-(a-b)²
RHS=4ab
(a+b)²-(a-b)²
=a²+2ab+b²-(a²-2ab+b²)
=a²+2ab+b²-a²+2ab-b²
=2ab+2ab[cutting a² and b²]
=4ab=RHS[proved]
✯Identity✯
(x + y)2 = x2 + 2xy + y2
(x – y)2 = x2 – 2xy + y2
x2 – y2 = (x + y) (x – y)
(x + a) (x + b) = x2 + (a + b)x + ab.
(x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx.
(x + y)3 = x3 + y3 + 3xy(x + y)
(x – y)3 = x3 – y3 – 3xy(x – y)
x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)
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