Math, asked by karnkamal990, 6 days ago

The value of (a + b) ^2 − (a − b) ^2 is…….​

Answers

Answered by pratikborate272
0

Answer:

4ab

Step-by-step explanation:

Given, (a+b)2−(a−b)2.

We know, (a+b)2 =a2+b2+2ab

and (a−b)2 a2+b2−2ab.

Then,

(a+b)2−(a−b)2

=a2+b2+2ab−(a2+b2−2ab)

=a2+b2+2ab−a2−b2+2ab

=4ab.

Answered by NewGeneEinstein
0

Lets Find:-

\\ \sf\longmapsto (a+b)^2-(a-b)^2

\boxed{\sf (a+b)^2=a^2+2ab+b^2}

\boxed{\sf (a-b)^2=a^2-2ab+b^2}

\\ \sf\longmapsto a^2+2ab+b^2-a^2-2ab+b^2

  • Combine like terms

\\ \sf\longmapsto a^2-a^2+2ab-2ab+b^2+b^2

\\ \sf\longmapsto 0+0+2b^2

\\ \sf\longmapsto 2b^2

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