Question

The value of (a-b)+(b-c)+(c-a) is​

Answer 1

Answer: (1) 0

Solution: Since, a−b+b−c+c−a=0

Vectors a−b,b−c and c−a are coplanar, therefore

[a−b b−c c−a]=0

Answer 2

Answer:

a² + b² + c²

=(a-b)+(b-c+c-a)

=(a-b) + b-c²-a

=(a)-b+b-c²-a

=(a)+a+b²+c²

=a²+b²+c²

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