Question

The value of a car depreciate 20% every year if after two year the price of a car is rupees 20 8000 find its original price

Answer 1

Answer:

rupees 325000

Step-by-step explanation:

The value of the car,V, after t years is given as;

$V_{t}=C*(1-\frac{rate}{100}) ^{t}$

Therefore

$8000=C*(1-\frac{20}{100})^{2}  \\8000=C*(1-0.2)^2\\8000=C*0.8^2$

making C the subject of the formula we get

$C=\frac{208000}{0.8^2}\\C=\frac{208000}{0.64} \\C=325000$