The value of 'a' for which one root of the quadratic
equation (a? – 5a +3)x2 – (3a – 1)x + 2 = 0 is
twice as large as other is
Answers
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Step-by-step explanation:
a
2
−5a+3)x
2
+(3a−1)x+2=0
Let the roots be α
1
β, given β=2α
⇒3α=
(a
2
−5a+3)
−(3a−1)
…(1) (Sum of roots)
⇒2α
2
=
a
2
−5a+3
2
…(2) (Product of roots)
⇒
(a
2
−5a+3)
2
(3a−1)
2
=
a
2
−5a+3
9
⇒
(a
2
−5a+3)
2
(3a−1)
2
−9(a
2
−5a+3)
=0
⇒9a
2
−6a+1−9a
2
+45a−27=0
⇒39a−26=0
⇒a=
3
2
chhayatrivedi11:
good
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