the value of a for which the lines x=1,y=2 and a^2 x+2y 20=0 are concurrent,is
Answers
Answered by
0
Answer:
Since
x
=
1
,
y
=
2
and
a
2
x
+
2
y
−
20
=
0
are concurrent
∴
x
=
1
and
y
=
2
lie on the line
a
2
x
+
2
y
−
20
=
0
⇒
x
=
1
and
y
=
2
is a solution of given equation.
On substituting
x
=
1
and
y
=
2
in equation
a
2
x
+
2
y
−
20
=
0
, we get
⇒
a
2
×
1
+
2
×
2
−
20
=
0
⇒
a
2
−
16
=
0
⇒
a
2
=
16
⇒
a
=
−
4
o
r
4
Answered by
2
= a * 0, y = 10/a^2
= a ==/- 1
= y = 10
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