The value of a for which the lines x=1, y=2 and a(a)x+2y-20=0 are concurrent , is *
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Since ,x=1, y=2 and a2x+2y−20=0are concurrent∴x=1 andy=2lie on the line a2x+2y−20=0⇒x=1 and y=2 is a solution of given equation.On substituting x=1and y=2in equation a2x+2y−20=0, we get⇒a2×1+2×2−20=0⇒a2-16=0⇒a2=16⇒a=−4or 4
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